X^2+4x-700=0

Solution for X^2+4x-700=0 equation:

X^2+4X-700=0

a = 1; b = 4; c = -700;
Δ = b2-4ac
Δ = 42-4·1·(-700)
Δ = 2816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2816}=\sqrt{256*11}=\sqrt{256}*\sqrt{11}=16\sqrt{11}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-16\sqrt{11}}{2*1}=\frac{-4-16\sqrt{11}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+16\sqrt{11}}{2*1}=\frac{-4+16\sqrt{11}}{2}
$